0=-16^2+120x

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Solution for 0=-16^2+120x equation: 



0=-16^2+120x

We move all terms to the left:

0-(-16^2+120x)=0

We add all the numbers together, and all the variables

-(-16^2+120x)=0

We get rid of parentheses

-120x+16^2=0

We add all the numbers together, and all the variables

-120x+256=0

We move all terms containing x to the left, all other terms to the right

-120x=-256

x=-256/-120

x=2+2/15

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